(-4b^2)-25=(-1)-2b-5b^2

Solution for (-4b^2)-25=(-1)-2b-5b^2 equation:

(-4b^2)-25=(-1)-2b-5b^2

We move all terms to the left:

(-4b^2)-25-((-1)-2b-5b^2)=0

We get rid of parentheses

-4b^2-((-1)-2b-5b^2)-25=0


We calculate terms in parentheses: -((-1)-2b-5b^2), so:

(-1)-2b-5b^2

determiningTheFunctionDomain
-5b^2-2b+(-1)

We add all the numbers together, and all the variables

-5b^2-2b-1

Back to the equation:

-(-5b^2-2b-1)


We get rid of parentheses

-4b^2+5b^2+2b+1-25=0

We add all the numbers together, and all the variables

b^2+2b-24=0

a = 1; b = 2; c = -24;
Δ = b2-4ac
Δ = 22-4·1·(-24)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-10}{2*1}=\frac{-12}{2}
=-6
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+10}{2*1}=\frac{8}{2}
=4
$